Determine the zeros of a polynomial function with real coefficients.
Subsection4.5.1Activities
Remark4.5.1.
Recall that to find the \(x\)-intercepts of a function \(f(x)\text{,}\) we need to find the values of \(x\) that make \(f(x)=0\text{.}\) We saw in Section 1.5 that the zero product property (Definition 1.5.3) was helpful when \(f(x)\) is a polynomial that we can factor. Let’s consider how we approach polynomials which are not in factored form or easily factorable.
Activity4.5.2.
Consider the function \(f(x)=x^3 - 7 x^2 + 7 x + 15\text{.}\)
(a)
Use polynomial division from Section 4.4 to divide \(f(x)\) by \(x-2\text{.}\) What is the remainder?
Answer.
\(9\)
(b)
Find \(f(2)\text{.}\) What do you notice?
Answer.
\(f(2)=9\) Remainder and value are the same
Theorem4.5.3.Remainder Theorem.
If a polynomial \(p(x)\) is divided by \(x-a\) then the remainder is equal to \(p(a)\text{.}\)
Activity4.5.4.
Again consider the function \(f(x)=x^3 - 7 x^2 + 7 x + 15\text{.}\)
(a)
Divide \(f(x)\) by \(x-3\text{.}\) What is the remainder?
Answer.
\(0\)
(b)
Find \(f(3)\text{.}\) What do you notice?
Answer.
\(f(3)=0\) When value is 0 there is no remainder
Theorem4.5.5.Factor Theorem.
A number \(a\) is a zero of a polynomial function \(p(x)\) (that is, \(p(a)=0\)) if and only if \(x-a\) is a factor of \(p(x)\text{.}\)
Remark4.5.6.
\(x-a\)\(a\)
Activity4.5.7.
One more time consider the function \(f(x)=x^3 - 7 x^2 + 7 x + 15\text{.}\)
(a)
We already know from Activity 4.5.4 that \(x-3\) is a factor of the polynomial \(f(x)\text{.}\) Use division to express \(f(x)\) as \((x-3)\cdot q(x)\text{,}\) where \(q(x)\) is a quadratic function.
\(\displaystyle q(x)=x^2-2x-3\)
\(\displaystyle q(x)=x^2-10x-37\)
\(\displaystyle q(x)=x^2-4x-5\)
\(\displaystyle q(x)=x^2+4x-5\)
Answer.
D
(b)
Notice that \(q(x)\) is something we can factor. Factor this quadratic and find the remaining zeros.
Consider the function \(f(x) = 18 x^4 + 67 x^3 - 81 x^2 - 202 x + 168\text{.}\)
(a)
Graph the function. According to the graph, what value(s) seem to be zeros?
Answer.
\(-4\) and \(-2\)
(b)
Use the Remainder Theorem to confirm that your guesses are actually zeros.
Answer.
\(f(-4)=0\) and \(f(-2)=0\)
(c)
Now use these zeros along with polynomial division to rewrite the function as \(f(x)=(x-a)(x-b)q(x)\) where \(a\) and \(b\) are zeros and \(q(x)\) is the remaining quadratic function.
Answer.
\((x+4)(x+2)(18x^2-41x+21)\)
(d)
Solve the quadratic \(q(x)\) to find the remaining zeros.
Answer.
\(\dfrac{3}{2}\) and \(\dfrac{7}{9}\)
(e)
List all zeros of \(f(x)\text{.}\)
Answer.
\(-4, -2, \dfrac{7}{9}, \dfrac{3}{2}\)
(f)
Rewrite \(f(x)\) as a product of linear factors.
Answer.
\((x+4)(x+2)(2x-3)(9x-7)\)
Remark4.5.10.
Activity4.5.11.
Consider the quadratic function \(f(x)=(2x-5)(3x-8)=6x^2-31x+40\text{.}\)
(a)
What are the roots of this quadratic?
Answer.
\(\dfrac{5}{2}\) and \(\dfrac{8}{3}\)
(b)
What do you notice about these roots in relation to the factors of \(a=6\) and \(c=40\) in \(f(x)=6x^2-31x+40\text{?}\)
Answer.
The numerator is a factor of \(c\) and the denominator is a factor of \(a\text{.}\)
If a polynomial \(p(x)=a_nx^n+x_{n-1}x^{n-1}+\cdots +a_1x+a_0 \) has integer coefficients, then the rational zeros have the form \(\dfrac{p}{q}\) where \(p\) is a factor of the constant term \(a_0\) and \(q\) is a factor of the leading coefficient \(a_n\text{.}\)
Activity4.5.14.
Consider the polynomial \(f(x)=5x^3-2x^2+20x-8\text{.}\)
(a)
List the factors of the constant term.
Answer.
\(\pm 8, \pm 4, \pm 2 \pm 1\)
(b)
List the factors of the leading coefficient.
Answer.
\(\pm 5, \pm 1\)
(c)
Use parts (a) and (b) to list all the possible rational roots.
Let \(p(x)\) be a polynomial function with real coefficients. If \(a+bi\text{,}\) is a complex zero of the function, then the conjugate \(a-bi\) is also a zero of the function. These two zeroes are called conjugate zeros, or a conjugate pair of zeros.
Activity4.5.18.
Consider the function \(f(x)=x^5+3x^4+4x^3+8x^2-16\text{.}\)
(a)
Use a graphing utility to graph \(f(x)\text{.}\)
Answer.
(b)
Find all the zeros of \(f(x)\) and their corresponding multiplicities.
Answer.
\(f(x)\) has zeros at \(-2\text{,}\)\(1\text{,}\)\(-2i\text{,}\) and \(2i\text{,}\) all of multiplicity 1 except \(-2\) has multiplicity 2
Activity4.5.19.
Consider the following information about a polynomial \(f(x)\text{:}\)
\(x=2\) is a zero with multiplicity \(1\)
\(x=-1\) is a zero with multiplicity \(2\)
\(x=i\) is a zero with multiplicity \(1\)
(a)
What is the smallest possible degree of such a polynomial \(f(x)\) with real coefficients?
\(\displaystyle 2\)
\(\displaystyle 3\)
\(\displaystyle 4\)
\(\displaystyle 5\)
\(\displaystyle 6\)
Answer.
D
(b)
Write an expression for such a polynomial \(f(x)\) with real coefficients of smallest possible degree.
Answer.
\(f(x)=(x-2)(x-1)^2(x^2+1)=x^5-4x^4+6x^3-6x^2+5x-2\) is one such polynomial.